2(x^2+2x+4)=0

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Solution for 2(x^2+2x+4)=0 equation:



2(x^2+2x+4)=0
We multiply parentheses
2x^2+4x+8=0
a = 2; b = 4; c = +8;
Δ = b2-4ac
Δ = 42-4·2·8
Δ = -48
Delta is less than zero, so there is no solution for the equation

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